# To get a particular bit from a number

This program is to get a particular bit from a number

To solve this problem we will be taking two approach:

First Approach:
Right shift the number by that bit, and(&) that 1. If the result is 1 means that bit is 1 else 0

``````#include <stdio.h>

int find_bit (int num, int pos)
{
return ((num >> pos) & 1);
}

int main()
{
int num, pos;
printf("\n Enter the number: ");
scanf("%d", &num);
printf("\n Enter the position: ");
scanf("%d", &pos);

int res = find_bit(num, pos -1);
if(res)
printf("\n The given bit is 1\n");
else
printf("\n The given bit is 0 \n");
return 0;
}``````

Output:

`````` Enter the number: 8
Enter the position: 4

The given bit is 1``````

Second Approach:
In this we do not right shift the number rather we get the another number such that all the bit if that number is 0 except the bit given. And then we and(&) the original number with the second number. If the result is 1, the given bit is 1 else 0.

``````#include <stdio.h>

int find_bit (int num, int pos)
{
/* This gives us the number where all bit is unset except at position "pos" */
int mask = 1UL << pos;
}

int main()
{
int num, pos;
printf("\n Enter the number: ");
scanf("%d", &num);
printf("\n Enter the position: ");
scanf("%d", &pos);

int res = find_bit(num, pos);
if(res)
printf("\n The given bit is 1\n");
else
printf("\n The given bit is 0 \n");
return 0;
}``````

Output:

`````` Enter the number: 7
Enter the position: 3

The given bit is 1``````

Categories: C Language